DATA STRUCTURES & ALGORITHMS – FULL COURSE NOTES
Below is a complete, self-contained DSA course note set with every code example in both C++ and Python, organized by modules. All code is tested, concise, and production-ready for interviews (LeetCode-style).
DATA STRUCTURES & ALGORITHMS – FULL COURSE NOTES With C++ & Python Code Examples
DATA STRUCTURES & ALGORITHMS – FULL COURSE NOTES With C++ & Python Code Examples
Below is a complete, self-contained DSA course note set with every code example in both C++ and Python, organized by modules.
All code is tested, concise, and production-ready for interviews (LeetCode-style).
DATA STRUCTURES & ALGORITHMS – FULL COURSE NOTES
With C++ & Python Code Examples
MODULE 0 – COMPLEXITY ANALYSIS
| Notation | Meaning |
|---|---|
| O(f(n)) | Upper bound |
| Ω(f(n)) | Lower bound |
| Θ(f(n)) | Tight bound |
Master Theorem
For T(n) = aT(n/b) + f(n):
If f(n) = O(n^log_b(a) - ε) → T(n) = Θ(n^log_b(a))
If f(n) = Θ(n^log_b(a)) → T(n) = Θ(n^log_b(a) log n)
If f(n) = Ω(n^log_b(a) + ε) → T(n) = Θ(f(n))
MODULE 1 – ARRAYS & STRINGS
1. Two Sum
// C++
vector<int> twoSum(vector<int>& nums, int target) {
unordered_map<int, int> mp;
for (int i = 0; i < nums.size(); i++) {
int comp = target - nums[i];
if (mp.count(comp)) return {mp[comp], i};
mp[nums[i]] = i;
}
return {};
}
# Python
def twoSum(nums, target):
mp = {}
for i, n in enumerate(nums):
if target - n in mp:
return [mp[target - n], i]
mp[n] = i
return []
2. Trapping Rain Water
// C++ - Two Pointers
int trap(vector<int>& height) {
int n = height.size(), l = 0, r = n-1;
int leftMax = 0, rightMax = 0, water = 0;
while (l < r) {
if (height[l] < height[r]) {
leftMax = max(leftMax, height[l]);
water += leftMax - height[l++];
} else {
rightMax = max(rightMax, height[r]);
water += rightMax - height[r--];
}
}
return water;
}
# Python
def trap(height):
l, r = 0, len(height)-1
leftMax = rightMax = water = 0
while l < r:
if height[l] < height[r]:
leftMax = max(leftMax, height[l])
water += leftMax - height[l]
l += 1
else:
rightMax = max(rightMax, height[r])
water += rightMax - height[r]
r -= 1
return water
3. Longest Substring Without Repeating
// C++
int lengthOfLongestSubstring(string s) {
unordered_map<char, int> lastSeen;
int maxLen = 0, start = 0;
for (int i = 0; i < s.size(); i++) {
if (lastSeen.count(s[i]) && lastSeen[s[i]] >= start)
start = lastSeen[s[i]] + 1;
lastSeen[s[i]] = i;
maxLen = max(maxLen, i - start + 1);
}
return maxLen;
}
# Python
def lengthOfLongestSubstring(s):
lastSeen = {}
maxLen = start = 0
for i, c in enumerate(s):
if c in lastSeen and lastSeen[c] >= start:
start = lastSeen[c] + 1
lastSeen[c] = i
maxLen = max(maxLen, i - start + 1)
return maxLen
4. Merge Intervals
// C++
vector<vector<int>> merge(vector<vector<int>>& intervals) {
if (intervals.empty()) return {};
sort(intervals.begin(), intervals.end());
vector<vector<int>> res = {intervals[0]};
for (auto& curr : intervals) {
if (res.back()[1] >= curr[0])
res.back()[1] = max(res.back()[1], curr[1]);
else
res.push_back(curr);
}
return res;
}
# Python
def merge(intervals):
if not intervals: return []
intervals.sort()
res = [intervals[0]]
for curr in intervals[1:]:
if res[-1][1] >= curr[0]:
res[-1][1] = max(res[-1][1], curr[1])
else:
res.append(curr)
return res
MODULE 2 – LINKED LISTS
1. Reverse Linked List
// C++
ListNode* reverseList(ListNode* head) {
ListNode *prev = nullptr, *curr = head;
while (curr) {
ListNode* next = curr->next;
curr->next = prev;
prev = curr;
curr = next;
}
return prev;
}
# Python
def reverseList(head):
prev = None
curr = head
while curr:
next_node = curr.next
curr.next = prev
prev = curr
curr = next_node
return prev
2. Detect Cycle (Floyd’s)
// C++
bool hasCycle(ListNode *head) {
ListNode *slow = head, *fast = head;
while (fast && fast->next) {
slow = slow->next;
fast = fast->next->next;
if (slow == fast) return true;
}
return false;
}
# Python
def hasCycle(head):
slow = fast = head
while fast and fast.next:
slow = slow.next
fast = fast.next.next
if slow == fast: return True
return False
3. Merge Two Sorted Lists
// C++
ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) {
ListNode dummy(0), *tail = &dummy;
while (l1 && l2) {
if (l1->val < l2->val) { tail->next = l1; l1 = l1->next; }
else { tail->next = l2; l2 = l2->next; }
tail = tail->next;
}
tail->next = l1 ? l1 : l2;
return dummy.next;
}
# Python
def mergeTwoLists(l1, l2):
dummy = ListNode(0)
tail = dummy
while l1 and l2:
if l1.val < l2.val:
tail.next = l1
l1 = l1.next
else:
tail.next = l2
l2 = l2.next
tail = tail.next
tail.next = l1 if l1 else l2
return dummy.next
MODULE 3 – STACKS & QUEUES
1. Valid Parentheses
// C++
bool isValid(string s) {
stack<char> st;
for (char c : s) {
if (c == '(' || c == '{' || c == '[') st.push(c);
else {
if (st.empty()) return false;
char top = st.top(); st.pop();
if ((c == ')' && top != '(') ||
(c == '}' && top != '{') ||
(c == ']' && top != '[')) return false;
}
}
return st.empty();
}
# Python
def isValid(s):
stack = []
pairs = {')':'(', '}':'{', ']':'['}
for c in s:
if c in pairs:
if not stack or stack.pop() != pairs[c]:
return False
else:
stack.append(c)
return not stack
2. Next Greater Element (Monotonic Stack)
// C++
vector<int> nextGreaterElement(vector<int>& nums) {
int n = nums.size();
vector<int> res(n, -1);
stack<int> st;
for (int i = 0; i < n; i++) {
while (!st.empty() && nums[st.top()] < nums[i]) {
res[st.top()] = nums[i];
st.pop();
}
st.push(i);
}
return res;
}
# Python
def nextGreaterElement(nums):
n = len(nums)
res = [-1] * n
stack = []
for i in range(n):
while stack and nums[stack[-1]] < nums[i]:
res[stack.pop()] = nums[i]
stack.append(i)
return res
MODULE 4 – TREES
1. Inorder Traversal (Iterative)
// C++
vector<int> inorderTraversal(TreeNode* root) {
vector<int> res;
stack<TreeNode*> st;
TreeNode* curr = root;
while (curr || !st.empty()) {
while (curr) {
st.push(curr);
curr = curr->left;
}
curr = st.top(); st.pop();
res.push_back(curr->val);
curr = curr->right;
}
return res;
}
# Python
def inorderTraversal(root):
res, stack = [], []
curr = root
while curr or stack:
while curr:
stack.append(curr)
curr = curr.left
curr = stack.pop()
res.append(curr.val)
curr = curr.right
return res
2. Binary Tree Level Order
// C++
vector<vector<int>> levelOrder(TreeNode* root) {
if (!root) return {};
vector<vector<int>> res;
queue<TreeNode*> q;
q.push(root);
while (!q.empty()) {
int size = q.size();
vector<int> level;
for (int i = 0; i < size; i++) {
TreeNode* node = q.front(); q.pop();
level.push_back(node->val);
if (node->left) q.push(node->left);
if (node->right) q.push(node->right);
}
res.push_back(level);
}
return res;
}
# Python
def levelOrder(root):
if not root: return []
res, q = [], [root]
while q:
level = []
for _ in range(len(q)):
node = q.pop(0)
level.append(node.val)
if node.left: q.append(node.left)
if node.right: q.append(node.right)
res.append(level)
return res
3. Lowest Common Ancestor (BST)
// C++
TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q) {
if (!root || !p || !q) return nullptr;
if (root->val > max(p->val, q->val)) return lowestCommonAncestor(root->left, p, q);
if (root->val < min(p->val, q->val)) return lowestCommonAncestor(root->right, p, q);
return root;
}
# Python
def lowestCommonAncestor(root, p, q):
if not root: return None
if root.val > max(p.val, q.val):
return lowestCommonAncestor(root.left, p, q)
if root.val < min(p.val, q.val):
return lowestCommonAncestor(root.right, p, q)
return root
MODULE 5 – HEAPS
1. Kth Largest Element
// C++ - Min Heap
int findKthLargest(vector<int>& nums, int k) {
priority_queue<int, vector<int>, greater<int>> pq;
for (int num : nums) {
pq.push(num);
if (pq.size() > k) pq.pop();
}
return pq.top();
}
# Python
import heapq
def findKthLargest(nums, k):
return heapq.nlargest(k, nums)[-1]
2. Merge K Sorted Lists
// C++ - Min Heap
ListNode* mergeKLists(vector<ListNode*>& lists) {
auto comp = [](ListNode* a, ListNode* b) { return a->val > b->val; };
priority_queue<ListNode*, vector<ListNode*>, decltype(comp)> pq(comp);
for (auto l : lists) if (l) pq.push(l);
ListNode dummy(0), *tail = &dummy;
while (!pq.empty()) {
ListNode* node = pq.top(); pq.pop();
tail->next = node;
tail = tail->next;
if (node->next) pq.push(node->next);
}
return dummy.next;
}
# Python
import heapq
def mergeKLists(lists):
heap = []
for i, l in enumerate(lists):
if l: heapq.heappush(heap, (l.val, i, l))
dummy = ListNode(0)
tail = dummy
while heap:
val, i, node = heapq.heappop(heap)
tail.next = node
tail = tail.next
if node.next:
heapq.heappush(heap, (node.next.val, i, node.next))
return dummy.next
MODULE 6 – HASHING
1. LRU Cache
// C++
class LRUCache {
int cap;
list<pair<int,int>> dll;
unordered_map<int, list<pair<int,int>>::iterator> mp;
public:
LRUCache(int capacity) : cap(capacity) {}
int get(int key) {
if (mp.find(key) == mp.end()) return -1;
dll.splice(dll.begin(), dll, mp[key]);
mp[key] = dll.begin();
return dll.begin()->second;
}
void put(int key, int value) {
if (get(key) != -1) { dll.begin()->second = value; return; }
if (dll.size() == cap) {
int del = dll.back().first;
dll.pop_back();
mp.erase(del);
}
dll.push_front({key, value});
mp[key] = dll.begin();
}
};
# Python
class ListNode:
def __init__(self, key=0, val=0):
self.key = key
self.val = val
self.prev = self.next = None
class LRUCache:
def __init__(self, capacity):
self.cap = capacity
self.cache = {}
self.left = self.right = ListNode()
self.left.next = self.right
self.right.prev = self.left
def _remove(self, node):
node.prev.next = node.next
node.next.prev = node.prev
def _add(self, node):
prev = self.right.prev
prev.next = node
node.prev = prev
node.next = self.right
self.right.prev = node
def get(self, key):
if key in self.cache:
self._remove(self.cache[key])
self._add(self.cache[key])
return self.cache[key].val
return -1
def put(self, key, value):
if key in self.cache:
self._remove(self.cache[key])
node = ListNode(key, value)
self.cache[key] = node
self._add(node)
if len(self.cache) > self.cap:
lru = self.left.next
self._remove(lru)
del self.cache[lru.key]
MODULE 7 – GRAPHS
1. BFS (Shortest Path)
// C++
vector<int> shortestPath(vector<vector<int>>& adj, int src) {
int n = adj.size();
vector<int> dist(n, -1);
queue<int> q;
q.push(src); dist[src] = 0;
while (!q.empty()) {
int u = q.front(); q.pop();
for (int v : adj[u]) {
if (dist[v] == -1) {
dist[v] = dist[u] + 1;
q.push(v);
}
}
}
return dist;
}
# Python
from collections import deque
def shortestPath(adj, src):
n = len(adj)
dist = [-1] * n
q = deque([src])
dist[src] = 0
while q:
u = q.popleft()
for v in adj[u]:
if dist[v] == -1:
dist[v] = dist[u] + 1
q.append(v)
return dist
2. Dijkstra
// C++
vector<int> dijkstra(vector<vector<pair<int,int>>>& graph, int src) {
int n = graph.size();
vector<int> dist(n, INT_MAX);
priority_queue<pair<int,int>, vector<pair<int,int>>, greater<>> pq;
dist[src] = 0; pq.push({0, src});
while (!pq.empty()) {
auto [d, u] = pq.top(); pq.pop();
if (d > dist[u]) continue;
for (auto [v, w] : graph[u]) {
if (dist[u] + w < dist[v]) {
dist[v] = dist[u] + w;
pq.push({dist[v], v});
}
}
}
return dist;
}
# Python
import heapq
def dijkstra(graph, src):
n = len(graph)
dist = [float('inf')] * n
dist[src] = 0
pq = [(0, src)]
while pq:
d, u = heapq.heappop(pq)
if d > dist[u]: continue
for v, w in graph[u]:
if dist[u] + w < dist[v]:
dist[v] = dist[u] + w
heapq.heappush(pq, (dist[v], v))
return dist
MODULE 8 – DYNAMIC PROGRAMMING
1. 0/1 Knapsack
// C++
int knapsack(vector<int>& wt, vector<int>& val, int W) {
int n = wt.size();
vector<vector<int>> dp(n+1, vector<int>(W+1, 0));
for (int i = 1; i <= n; i++) {
for (int w = 1; w <= W; w++) {
if (wt[i-1] <= w)
dp[i][w] = max(val[i-1] + dp[i-1][w-wt[i-1]], dp[i-1][w]);
else
dp[i][w] = dp[i-1][w];
}
}
return dp[n][W];
}
# Python
def knapsack(wt, val, W):
n = len(val)
dp = [[0]*(W+1) for _ in range(n+1)]
for i in range(1, n+1):
for w in range(1, W+1):
if wt[i-1] <= w:
dp[i][w] = max(val[i-1] + dp[i-1][w-wt[i-1]], dp[i-1][w])
else:
dp[i][w] = dp[i-1][w]
return dp[n][W]
2. Longest Common Subsequence
// C++
int longestCommonSubsequence(string text1, string text2) {
int n = text1.size(), m = text2.size();
vector<vector<int>> dp(n+1, vector<int>(m+1, 0));
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= m; j++) {
if (text1[i-1] == text2[j-1])
dp[i][j] = dp[i-1][j-1] + 1;
else
dp[i][j] = max(dp[i-1][j], dp[i][j-1]);
}
}
return dp[n][m];
}
# Python
def longestCommonSubsequence(text1, text2):
n, m = len(text1), len(text2)
dp = [[0]*(m+1) for _ in range(n+1)]
for i in range(1, n+1):
for j in range(1, m+1):
if text1[i-1] == text2[j-1]:
dp[i][j] = dp[i-1][j-1] + 1
else:
dp[i][j] = max(dp[i-1][j], dp[i][j-1])
return dp[n][m]
MODULE 9 – ADVANCED
1. Union-Find (DSU)
// C++
class DSU {
vector<int> parent, rank;
public:
DSU(int n) {
parent.resize(n); rank.resize(n, 0);
for (int i = 0; i < n; i++) parent[i] = i;
}
int find(int x) {
if (parent[x] != x) parent[x] = find(parent[x]);
return parent[x];
}
void union_sets(int x, int y) {
int px = find(x), py = find(y);
if (px == py) return;
if (rank[px] < rank[py]) swap(px, py);
parent[py] = px;
if (rank[px] == rank[py]) rank[px]++;
}
};
# Python
class DSU:
def __init__(self, n):
self.parent = list(range(n))
self.rank = [0] * n
def find(self, x):
if self.parent[x] != x:
self.parent[x] = self.find(self.parent[x])
return self.parent[x]
def union(self, x, y):
px, py = self.find(x), self.find(y)
if px == py: return
if self.rank[px] < self.rank[py]:
px, py = py, px
self.parent[py] = px
if self.rank[px] == self.rank[py]:
self.rank[px] += 1
All code is ready to copy-paste into LeetCode/IDE.
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DATA STRUCTURES & ALGORITHMS – FULL COURSE NOTES
Below is a complete, self-contained DSA course note set with every code example in both C++ and Python, organized by modules. All code is tested, concise, and production-ready for interviews (LeetCode-style).
DATA STRUCTURES & ALGORITHMS – FULL COURSE NOTES With C++ & Python Code Examples
DATA STRUCTURES & ALGORITHMS – FULL COURSE NOTES With C++ & Python Code Examples
Below is a complete, self-contained DSA course note set with every code example in both C++ and Python, organized by modules.
All code is tested, concise, and production-ready for interviews (LeetCode-style).
DATA STRUCTURES & ALGORITHMS – FULL COURSE NOTES
With C++ & Python Code Examples
MODULE 0 – COMPLEXITY ANALYSIS
| Notation | Meaning |
|---|---|
| O(f(n)) | Upper bound |
| Ω(f(n)) | Lower bound |
| Θ(f(n)) | Tight bound |
Master Theorem
For T(n) = aT(n/b) + f(n):
If f(n) = O(n^log_b(a) - ε) → T(n) = Θ(n^log_b(a))
If f(n) = Θ(n^log_b(a)) → T(n) = Θ(n^log_b(a) log n)
If f(n) = Ω(n^log_b(a) + ε) → T(n) = Θ(f(n))
MODULE 1 – ARRAYS & STRINGS
1. Two Sum
// C++
vector<int> twoSum(vector<int>& nums, int target) {
unordered_map<int, int> mp;
for (int i = 0; i < nums.size(); i++) {
int comp = target - nums[i];
if (mp.count(comp)) return {mp[comp], i};
mp[nums[i]] = i;
}
return {};
}
# Python
def twoSum(nums, target):
mp = {}
for i, n in enumerate(nums):
if target - n in mp:
return [mp[target - n], i]
mp[n] = i
return []
2. Trapping Rain Water
// C++ - Two Pointers
int trap(vector<int>& height) {
int n = height.size(), l = 0, r = n-1;
int leftMax = 0, rightMax = 0, water = 0;
while (l < r) {
if (height[l] < height[r]) {
leftMax = max(leftMax, height[l]);
water += leftMax - height[l++];
} else {
rightMax = max(rightMax, height[r]);
water += rightMax - height[r--];
}
}
return water;
}
# Python
def trap(height):
l, r = 0, len(height)-1
leftMax = rightMax = water = 0
while l < r:
if height[l] < height[r]:
leftMax = max(leftMax, height[l])
water += leftMax - height[l]
l += 1
else:
rightMax = max(rightMax, height[r])
water += rightMax - height[r]
r -= 1
return water
3. Longest Substring Without Repeating
// C++
int lengthOfLongestSubstring(string s) {
unordered_map<char, int> lastSeen;
int maxLen = 0, start = 0;
for (int i = 0; i < s.size(); i++) {
if (lastSeen.count(s[i]) && lastSeen[s[i]] >= start)
start = lastSeen[s[i]] + 1;
lastSeen[s[i]] = i;
maxLen = max(maxLen, i - start + 1);
}
return maxLen;
}
# Python
def lengthOfLongestSubstring(s):
lastSeen = {}
maxLen = start = 0
for i, c in enumerate(s):
if c in lastSeen and lastSeen[c] >= start:
start = lastSeen[c] + 1
lastSeen[c] = i
maxLen = max(maxLen, i - start + 1)
return maxLen
4. Merge Intervals
// C++
vector<vector<int>> merge(vector<vector<int>>& intervals) {
if (intervals.empty()) return {};
sort(intervals.begin(), intervals.end());
vector<vector<int>> res = {intervals[0]};
for (auto& curr : intervals) {
if (res.back()[1] >= curr[0])
res.back()[1] = max(res.back()[1], curr[1]);
else
res.push_back(curr);
}
return res;
}
# Python
def merge(intervals):
if not intervals: return []
intervals.sort()
res = [intervals[0]]
for curr in intervals[1:]:
if res[-1][1] >= curr[0]:
res[-1][1] = max(res[-1][1], curr[1])
else:
res.append(curr)
return res
MODULE 2 – LINKED LISTS
1. Reverse Linked List
// C++
ListNode* reverseList(ListNode* head) {
ListNode *prev = nullptr, *curr = head;
while (curr) {
ListNode* next = curr->next;
curr->next = prev;
prev = curr;
curr = next;
}
return prev;
}
# Python
def reverseList(head):
prev = None
curr = head
while curr:
next_node = curr.next
curr.next = prev
prev = curr
curr = next_node
return prev
2. Detect Cycle (Floyd’s)
// C++
bool hasCycle(ListNode *head) {
ListNode *slow = head, *fast = head;
while (fast && fast->next) {
slow = slow->next;
fast = fast->next->next;
if (slow == fast) return true;
}
return false;
}
# Python
def hasCycle(head):
slow = fast = head
while fast and fast.next:
slow = slow.next
fast = fast.next.next
if slow == fast: return True
return False
3. Merge Two Sorted Lists
// C++
ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) {
ListNode dummy(0), *tail = &dummy;
while (l1 && l2) {
if (l1->val < l2->val) { tail->next = l1; l1 = l1->next; }
else { tail->next = l2; l2 = l2->next; }
tail = tail->next;
}
tail->next = l1 ? l1 : l2;
return dummy.next;
}
# Python
def mergeTwoLists(l1, l2):
dummy = ListNode(0)
tail = dummy
while l1 and l2:
if l1.val < l2.val:
tail.next = l1
l1 = l1.next
else:
tail.next = l2
l2 = l2.next
tail = tail.next
tail.next = l1 if l1 else l2
return dummy.next
MODULE 3 – STACKS & QUEUES
1. Valid Parentheses
// C++
bool isValid(string s) {
stack<char> st;
for (char c : s) {
if (c == '(' || c == '{' || c == '[') st.push(c);
else {
if (st.empty()) return false;
char top = st.top(); st.pop();
if ((c == ')' && top != '(') ||
(c == '}' && top != '{') ||
(c == ']' && top != '[')) return false;
}
}
return st.empty();
}
# Python
def isValid(s):
stack = []
pairs = {')':'(', '}':'{', ']':'['}
for c in s:
if c in pairs:
if not stack or stack.pop() != pairs[c]:
return False
else:
stack.append(c)
return not stack
2. Next Greater Element (Monotonic Stack)
// C++
vector<int> nextGreaterElement(vector<int>& nums) {
int n = nums.size();
vector<int> res(n, -1);
stack<int> st;
for (int i = 0; i < n; i++) {
while (!st.empty() && nums[st.top()] < nums[i]) {
res[st.top()] = nums[i];
st.pop();
}
st.push(i);
}
return res;
}
# Python
def nextGreaterElement(nums):
n = len(nums)
res = [-1] * n
stack = []
for i in range(n):
while stack and nums[stack[-1]] < nums[i]:
res[stack.pop()] = nums[i]
stack.append(i)
return res
MODULE 4 – TREES
1. Inorder Traversal (Iterative)
// C++
vector<int> inorderTraversal(TreeNode* root) {
vector<int> res;
stack<TreeNode*> st;
TreeNode* curr = root;
while (curr || !st.empty()) {
while (curr) {
st.push(curr);
curr = curr->left;
}
curr = st.top(); st.pop();
res.push_back(curr->val);
curr = curr->right;
}
return res;
}
# Python
def inorderTraversal(root):
res, stack = [], []
curr = root
while curr or stack:
while curr:
stack.append(curr)
curr = curr.left
curr = stack.pop()
res.append(curr.val)
curr = curr.right
return res
2. Binary Tree Level Order
// C++
vector<vector<int>> levelOrder(TreeNode* root) {
if (!root) return {};
vector<vector<int>> res;
queue<TreeNode*> q;
q.push(root);
while (!q.empty()) {
int size = q.size();
vector<int> level;
for (int i = 0; i < size; i++) {
TreeNode* node = q.front(); q.pop();
level.push_back(node->val);
if (node->left) q.push(node->left);
if (node->right) q.push(node->right);
}
res.push_back(level);
}
return res;
}
# Python
def levelOrder(root):
if not root: return []
res, q = [], [root]
while q:
level = []
for _ in range(len(q)):
node = q.pop(0)
level.append(node.val)
if node.left: q.append(node.left)
if node.right: q.append(node.right)
res.append(level)
return res
3. Lowest Common Ancestor (BST)
// C++
TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q) {
if (!root || !p || !q) return nullptr;
if (root->val > max(p->val, q->val)) return lowestCommonAncestor(root->left, p, q);
if (root->val < min(p->val, q->val)) return lowestCommonAncestor(root->right, p, q);
return root;
}
# Python
def lowestCommonAncestor(root, p, q):
if not root: return None
if root.val > max(p.val, q.val):
return lowestCommonAncestor(root.left, p, q)
if root.val < min(p.val, q.val):
return lowestCommonAncestor(root.right, p, q)
return root
MODULE 5 – HEAPS
1. Kth Largest Element
// C++ - Min Heap
int findKthLargest(vector<int>& nums, int k) {
priority_queue<int, vector<int>, greater<int>> pq;
for (int num : nums) {
pq.push(num);
if (pq.size() > k) pq.pop();
}
return pq.top();
}
# Python
import heapq
def findKthLargest(nums, k):
return heapq.nlargest(k, nums)[-1]
2. Merge K Sorted Lists
// C++ - Min Heap
ListNode* mergeKLists(vector<ListNode*>& lists) {
auto comp = [](ListNode* a, ListNode* b) { return a->val > b->val; };
priority_queue<ListNode*, vector<ListNode*>, decltype(comp)> pq(comp);
for (auto l : lists) if (l) pq.push(l);
ListNode dummy(0), *tail = &dummy;
while (!pq.empty()) {
ListNode* node = pq.top(); pq.pop();
tail->next = node;
tail = tail->next;
if (node->next) pq.push(node->next);
}
return dummy.next;
}
# Python
import heapq
def mergeKLists(lists):
heap = []
for i, l in enumerate(lists):
if l: heapq.heappush(heap, (l.val, i, l))
dummy = ListNode(0)
tail = dummy
while heap:
val, i, node = heapq.heappop(heap)
tail.next = node
tail = tail.next
if node.next:
heapq.heappush(heap, (node.next.val, i, node.next))
return dummy.next
MODULE 6 – HASHING
1. LRU Cache
// C++
class LRUCache {
int cap;
list<pair<int,int>> dll;
unordered_map<int, list<pair<int,int>>::iterator> mp;
public:
LRUCache(int capacity) : cap(capacity) {}
int get(int key) {
if (mp.find(key) == mp.end()) return -1;
dll.splice(dll.begin(), dll, mp[key]);
mp[key] = dll.begin();
return dll.begin()->second;
}
void put(int key, int value) {
if (get(key) != -1) { dll.begin()->second = value; return; }
if (dll.size() == cap) {
int del = dll.back().first;
dll.pop_back();
mp.erase(del);
}
dll.push_front({key, value});
mp[key] = dll.begin();
}
};
# Python
class ListNode:
def __init__(self, key=0, val=0):
self.key = key
self.val = val
self.prev = self.next = None
class LRUCache:
def __init__(self, capacity):
self.cap = capacity
self.cache = {}
self.left = self.right = ListNode()
self.left.next = self.right
self.right.prev = self.left
def _remove(self, node):
node.prev.next = node.next
node.next.prev = node.prev
def _add(self, node):
prev = self.right.prev
prev.next = node
node.prev = prev
node.next = self.right
self.right.prev = node
def get(self, key):
if key in self.cache:
self._remove(self.cache[key])
self._add(self.cache[key])
return self.cache[key].val
return -1
def put(self, key, value):
if key in self.cache:
self._remove(self.cache[key])
node = ListNode(key, value)
self.cache[key] = node
self._add(node)
if len(self.cache) > self.cap:
lru = self.left.next
self._remove(lru)
del self.cache[lru.key]
MODULE 7 – GRAPHS
1. BFS (Shortest Path)
// C++
vector<int> shortestPath(vector<vector<int>>& adj, int src) {
int n = adj.size();
vector<int> dist(n, -1);
queue<int> q;
q.push(src); dist[src] = 0;
while (!q.empty()) {
int u = q.front(); q.pop();
for (int v : adj[u]) {
if (dist[v] == -1) {
dist[v] = dist[u] + 1;
q.push(v);
}
}
}
return dist;
}
# Python
from collections import deque
def shortestPath(adj, src):
n = len(adj)
dist = [-1] * n
q = deque([src])
dist[src] = 0
while q:
u = q.popleft()
for v in adj[u]:
if dist[v] == -1:
dist[v] = dist[u] + 1
q.append(v)
return dist
2. Dijkstra
// C++
vector<int> dijkstra(vector<vector<pair<int,int>>>& graph, int src) {
int n = graph.size();
vector<int> dist(n, INT_MAX);
priority_queue<pair<int,int>, vector<pair<int,int>>, greater<>> pq;
dist[src] = 0; pq.push({0, src});
while (!pq.empty()) {
auto [d, u] = pq.top(); pq.pop();
if (d > dist[u]) continue;
for (auto [v, w] : graph[u]) {
if (dist[u] + w < dist[v]) {
dist[v] = dist[u] + w;
pq.push({dist[v], v});
}
}
}
return dist;
}
# Python
import heapq
def dijkstra(graph, src):
n = len(graph)
dist = [float('inf')] * n
dist[src] = 0
pq = [(0, src)]
while pq:
d, u = heapq.heappop(pq)
if d > dist[u]: continue
for v, w in graph[u]:
if dist[u] + w < dist[v]:
dist[v] = dist[u] + w
heapq.heappush(pq, (dist[v], v))
return dist
MODULE 8 – DYNAMIC PROGRAMMING
1. 0/1 Knapsack
// C++
int knapsack(vector<int>& wt, vector<int>& val, int W) {
int n = wt.size();
vector<vector<int>> dp(n+1, vector<int>(W+1, 0));
for (int i = 1; i <= n; i++) {
for (int w = 1; w <= W; w++) {
if (wt[i-1] <= w)
dp[i][w] = max(val[i-1] + dp[i-1][w-wt[i-1]], dp[i-1][w]);
else
dp[i][w] = dp[i-1][w];
}
}
return dp[n][W];
}
# Python
def knapsack(wt, val, W):
n = len(val)
dp = [[0]*(W+1) for _ in range(n+1)]
for i in range(1, n+1):
for w in range(1, W+1):
if wt[i-1] <= w:
dp[i][w] = max(val[i-1] + dp[i-1][w-wt[i-1]], dp[i-1][w])
else:
dp[i][w] = dp[i-1][w]
return dp[n][W]
2. Longest Common Subsequence
// C++
int longestCommonSubsequence(string text1, string text2) {
int n = text1.size(), m = text2.size();
vector<vector<int>> dp(n+1, vector<int>(m+1, 0));
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= m; j++) {
if (text1[i-1] == text2[j-1])
dp[i][j] = dp[i-1][j-1] + 1;
else
dp[i][j] = max(dp[i-1][j], dp[i][j-1]);
}
}
return dp[n][m];
}
# Python
def longestCommonSubsequence(text1, text2):
n, m = len(text1), len(text2)
dp = [[0]*(m+1) for _ in range(n+1)]
for i in range(1, n+1):
for j in range(1, m+1):
if text1[i-1] == text2[j-1]:
dp[i][j] = dp[i-1][j-1] + 1
else:
dp[i][j] = max(dp[i-1][j], dp[i][j-1])
return dp[n][m]
MODULE 9 – ADVANCED
1. Union-Find (DSU)
// C++
class DSU {
vector<int> parent, rank;
public:
DSU(int n) {
parent.resize(n); rank.resize(n, 0);
for (int i = 0; i < n; i++) parent[i] = i;
}
int find(int x) {
if (parent[x] != x) parent[x] = find(parent[x]);
return parent[x];
}
void union_sets(int x, int y) {
int px = find(x), py = find(y);
if (px == py) return;
if (rank[px] < rank[py]) swap(px, py);
parent[py] = px;
if (rank[px] == rank[py]) rank[px]++;
}
};
# Python
class DSU:
def __init__(self, n):
self.parent = list(range(n))
self.rank = [0] * n
def find(self, x):
if self.parent[x] != x:
self.parent[x] = self.find(self.parent[x])
return self.parent[x]
def union(self, x, y):
px, py = self.find(x), self.find(y)
if px == py: return
if self.rank[px] < self.rank[py]:
px, py = py, px
self.parent[py] = px
if self.rank[px] == self.rank[py]:
self.rank[px] += 1
All code is ready to copy-paste into LeetCode/IDE.
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